Coulomb’s law for the magnitude of the force F between two particles with charges Q and Q separated by a distance d is | F |= K | QQ | d 2 , where K…

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October 18, 2020

Coulomb’s law for the magnitude of the force F

between two particles with charges  Q

 and  Q

separated by a distance d

 is

|F|=K|QQ

|

d

2

,

where K=1

4πϵ

0

, and ϵ

0

=8.854×10

−12

C

2

/(N⋅m

2

)

 is the permittivity of free space.

Consider two point charges located on the x axis: one charge, q

1

 = -19.0 nC

 , is located at x

1

 = -1.745 m

 ; the second charge, q

2

 = 36.0 nC

 , is at the origin (x=0.0000)

What is the net force exerted by these two charges on a third charge q

3

 = 52.5 nC

 placed between q

1

 and q

2

 at x

3

 = -1.060 m

 ?

Your answer may be positive or negative, depending on the direction of the force. 

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